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36x^2+56x-85=0
a = 36; b = 56; c = -85;
Δ = b2-4ac
Δ = 562-4·36·(-85)
Δ = 15376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15376}=124$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-124}{2*36}=\frac{-180}{72} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+124}{2*36}=\frac{68}{72} =17/18 $
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